— MLB Network (@MLBNetwork) October 7, 2017
Jay Bruce opened the season in New York, strolling to the plate while Jay-Z’s “Public Service Announcement” blared over the Citi Field speakers.
“Allow me to reintroduce myself…” the lyrics began.
But New York and Bruce have been acquainted for quite some time.
Bruce was first acquainted with the Yankees when they attempted to trade for him in August, at the waiver trade deadline. But a reluctance to take his entire salary off the Mets’ books landed him in Cleveland with the Indians, where he is currently tormenting the Yanks.
Bruce played the hero for the Indians in Game 1 of the ALDS on Thursday, and may have done the same thing on Friday with his second homer in as many nights. Bruce tied the wild game up with a solo four-bagger off Yankees’ reliever David Robertson in the eighth inning.
What was once a five-run Yankees lead was suddenly gone, with the game knotted at 8-8. The two teams have combined for five home runs, making for some exciting postseason fireworks.
The former Mets’ right fielder drove in three runs and scored twice in Game 1 of the series. While he had previously said that he was fine with remaining on the Mets following the non-waiver trade deadline, once he arrived in Cleveland and found himself in the thick of a playoff chase race, it was clear that he was happy to be there.
Shortly after being traded, Bruce, who went hitless for the Mets in the 2016 NL Wild Card game, said he went from the “least-fun” situation to the “most fun” situation.
It’s clear that he’s happy to be right where is.
“I couldn’t have fallen into a better situation,” Bruce said, after Game 1. “Obviously, when you get traded and you’re in trade rumors, it’s usually a contender or a team that’s contending at the moment. For whatever reason, I ended up here. Like I said, I know it sounds cliche, but I just want to do my part, man. And this has been a blast so far.”